Mr. Ochs Geometry Class
Chapter 2 answers to homework
Chapter 3 answes to homework
Chapter 8 Right Triangles
Similarity in a Right Triangle
Theorems Involving Pythagoras
Trigonometry and Applications
Answers to Ch8 worksheets
Chapter 9 Circles
Chapter 10 Construction and Loci
Construction #1 Copy a Segment
Constuction #2 Copy an Angle
Construction #3 Bisect an Angle
Construction #4 Bisect a Segment / Perpendicular Bisector
Construction #5 Perpendicular through a given point on a line
Construction #6 Perpendicular line through a point not on the line
Construction #7 Parallel line through a point not on the line using corresponding angles
Construction #8 Tangent line to a circle through a point ON the circle
Construction #9 Tangent line to a circle from a point in the exterior of the circle
Construction #10 Circumscribe a circle about a triangle
Construction #11 Inscribe a circle in a triangle
Construction #12 Dividing a segment into congruent parts
Construction #13 Construct a proportional segment to 3 given segments
Construction #14 construct the length of a geometric mean
Bisect a Segment
Perpendicular Bisector of a Segment
Find the midpoint of a segment
Divide a segment into 2 congruent segments
To see a video of Mr. Ochs doing examples
Mr Ochs Video
To see and example done in flash click on a link below
Math Open Ref
Math is Fun
Given a segment, construct the perpendicular bisector of the segment.
Construct the perpendicular bisector of segment BC.
1) Choose a radius for the compass that is larger than ½ the segment.
2) With this radius place your compass pointer on one endpoint of the segment and strike a semicircle(1/2 circle) that passes through the segment.
Keeping the same radius
repeat step 2 with the pointer on the other endpoint of the segment. The two semicircles will intersect.
Note: Eventually the semicircles can be reduced to two small arcs on either side of the segment.
4) With a straight edge draw a line through the points of intersection created by the arcs in steps 2 and 3.
Note 2 : This is how we find the midpoint of a segment.